For the given logic gate circuit, which of the following is the correct truth table?
0 | 0 | 0 |
0 | 1 | 1 |
1 | 1 | 0 |
1 | 0 | 1 |
0 | 0 | 1 |
0 | 1 | 0 |
1 | 1 | 1 |
1 | 0 | 0 |
0 | 0 | 1 |
0 | 1 | 0 |
1 | 1 | 0 |
1 | 0 | 0 |
0 | 0 | 1 |
0 | 1 | 1 |
1 | 1 | 0 |
1 | 0 | 0 |
Text Solution
Verified by ExpertsThe correct answer is:
D
The given logic circuit consists of an OR gate and a NAND gate.
The output of the OR gate is 
.
The inputs to the NAND gate are 
and 
.
The final output 
is given by 
.
Using Boolean algebra: 
.
Therefore, 
.
Let's verify this with the truth table:
0 | 0 | 0 | 1 |
0 | 1 | 1 | 1 |
1 | 1 | 1 | 0 |
1 | 0 | 1 | 0 |
Comparing this with the given options, option matches the calculated truth table.
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